Metoda parseDouble klasy Java Double zwraca nową wartość double, która jest inicjowana wartością odpowiadającą zdefiniowanemu Stringowi.

Ta metoda działa tak samo jak metoda valueOf() klasy Float.

mecz_preg

Składnia

 public static double parseDouble(String s) throws NumberFormatException 

Parametry

S- To jest ciąg do przeanalizowania.

Wartość zwracana

Metoda parseDouble() zwraca wartość double odpowiadającą przekazanemu parametrowi.

Rzuca

Metoda parseDouble() zgłasza:

1. Wyjątek NullPointerException — jeśli przekazany ciąg ma wartość null.

2. NumberFormatException- jeśli przekazany ciąg nie zawiera analizowalnego elementu zmiennoprzecinkowego.

Przykład 1

 public class Double_parseDoubleMethodExample1 { public static void main(String[] args) { String val1='1000'; String val2='156'; //here instead of adding it will concatenate two Strings //but will convert the String into Float Double d = Double.parseDouble(val1+val2); System.out.println('1. Sum ='+d); Double f1 = Double.parseDouble(val1)+Double.parseDouble(val2); System.out.println('2. Sum ='+f1); Double f2 = Double.parseDouble(val1)*Double.parseDouble(val2); System.out.println('3. Multiplication ='+f2); Double f3 = Double.parseDouble(val1)/Double.parseDouble(val2); System.out.println('4. Division ='+f3); Double f4 = Double.parseDouble(val1)%Double.parseDouble(val2); System.out.println('5. Reminder ='+f4); } } 

Wyjście:

darmowy ipconfig dla Linuksa

 1. Sum =1000156.0 2. Sum =1156.0 3. Multiplication =156000.0 4. Division =6.410256410256411 5. Reminder =64.0 

Przykład 2

 import java.util.Scanner; public class Double_parseDoubleMethodExample2 { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print(&apos;Enter your age:&apos;); String str = scanner.next(); // Double d1 = Double.parseDouble(str); Double d2 = 2018 - d1 ; System.out.println(&apos;Your year of birth is = &apos;+d2); if(d2<1965){ system.out.println('you are an adult, you eligible for the discount in railway tickets.'); } else{ double d3="d2-1965;" system.err.println('sorry! not eligible.try again after '+d3+' years'); < pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Enter your age:09 Sorry! You are not eligible.Try again after 44.0 years Your year of birth is = 2009.0 </pre> <h2>Example 3</h2> <pre> import java.util.Scanner; public class Double_parseDoubleMethodExample3 { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print(&apos;Enter any string:&apos;); String str = scanner.next(); Double d1= Double.parseDouble(str); System.out.println(&apos;Double value = &apos;+ d1); } } </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Enter any string:Himanshu@123 Exception in thread &apos;main&apos; java.lang.NumberFormatException: For input string: &apos;Himanshu@123&apos; at sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:2043) at sun.misc.FloatingDecimal.parseDouble(FloatingDecimal.java:110) at java.lang.Double.parseDouble(Double.java:538) </pre> <h2>Example 4</h2> <pre> import java.util.Scanner; public class Double_parseDoubleMethodExample4 { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); try { System.out.print(&apos;Enter any string:&apos;); String str = scanner.next(); Double d1 = Double.parseDouble(str); String str1=&apos;null&apos;; Double d2 = Double.parseDouble(str1); System.out.println(&apos;1. Double value = &apos; + d1); System.out.println(&apos;2. Double value = &apos; + d2); }catch (NullPointerException e){ System.out.println(&apos;An exception &apos;+e+&apos; has occured.
Plz enter a valid double integer&apos;); }catch (NumberFormatException ex){ System.out.println(&apos;An exception &apos;+ex+&apos; has occured.
Plz enter a valid double integer&apos;); } } } </pre> <span> Test it Now </span> <p> <strong>Output:</strong> </p> <pre> Enter any string:himanshu@123 An exception java.lang.NumberFormatException: For input string: &apos;himanshu@123&apos; has occured. Plz enter a valid double integer </pre> <br></1965){>

Przykład 3

 import java.util.Scanner; public class Double_parseDoubleMethodExample3 { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); System.out.print('Enter any string:'); String str = scanner.next(); Double d1= Double.parseDouble(str); System.out.println('Double value = '+ d1); } } 

Wyjście:

 Enter any string:Himanshu@123 Exception in thread 'main' java.lang.NumberFormatException: For input string: 'Himanshu@123' at sun.misc.FloatingDecimal.readJavaFormatString(FloatingDecimal.java:2043) at sun.misc.FloatingDecimal.parseDouble(FloatingDecimal.java:110) at java.lang.Double.parseDouble(Double.java:538) 

Przykład 4

 import java.util.Scanner; public class Double_parseDoubleMethodExample4 { public static void main(String[] args) { Scanner scanner = new Scanner(System.in); try { System.out.print('Enter any string:'); String str = scanner.next(); Double d1 = Double.parseDouble(str); String str1='null'; Double d2 = Double.parseDouble(str1); System.out.println('1. Double value = ' + d1); System.out.println('2. Double value = ' + d2); }catch (NullPointerException e){ System.out.println('An exception '+e+' has occured.
Plz enter a valid double integer'); }catch (NumberFormatException ex){ System.out.println('An exception '+ex+' has occured.
Plz enter a valid double integer'); } } } 

Wyjście:

 Enter any string:himanshu@123 An exception java.lang.NumberFormatException: For input string: 'himanshu@123' has occured. Plz enter a valid double integer